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検索キーワード「x^2+y^2=16 graph」に一致する投稿を表示しています

X^2/16 y^2/9=1 247121-X^2/9-y^2/16=1 hyperbola

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 x^2/16y^2/9=1 a^2=16 b^2=9 The center is (0,0) The xaxis is the major axis We know this because the x^2 term has the larger denominator We find the foci using the following equation and solving for c c^2=a^2b^2 c^2=169 c^2=7 c=sqrt(7) The coordinates for the foci are (c,0) > (sqrt(7),0)Equation at the end of step 1 ((9 • (x 2)) 24xy) 2 4 y 2 Step 2 Equation at the end of step 2 (3 2 x 2 24xy) 2 4 y 2 Step 3 Trying to factor a multi variable polynomial 31 Factoring 9x 2 24xy 16y 2 Try to factor this multivariable trinomial using trial and error1y=16(25)^x 2y=08(128)^x 3y=17(1/5)^x'' How do I determine if this equation is a linear function or a nonlinear function? 1 X^2/9-y^2/16=1 hyperbola